9v^2-46v^+5=0

Solution for 9v^2-46v^+5=0 equation:

9v^2-46v^+5=0

We add all the numbers together, and all the variables

9v^2-46v+5=0

a = 9; b = -46; c = +5;
Δ = b2-4ac
Δ = -462-4·9·5
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-44}{2*9}=\frac{2}{18}
=1/9
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+44}{2*9}=\frac{90}{18}
=5
$